下表为E型热电偶的分度表，已知冷端温度t0＝20℃，现测得热电动势E（t，t0）＝1.54mV，求被测端温度是多少度？表E型热电偶分度表（分度号：E，单位：mV）温度（℃）热电动势（mV）012345678900.0000.0590.1180.1760.2350.2950.3540.4130.4720.532100.5910.6510.7110.7700.8300.8900.9501.0111.0711.131201.1921.2521.3131.3731.4341.4951.5561.6171.6781.739301.8011.8621.9241.9852.0472.1092.1712.2332.2952.357402.4192.4822.5442.0572.6692.7322.7952.8582.9212.984

正确答案：解：由中间温度定律知：E（t，0）=E（t，20）+E（20，0）=1.54+1.192=2.732mV查表知，t=45℃