若已知2C(石墨)+O2(g)=2CO(g)(1)ΔrHmθ(298.15K)=-221.04kJ·mol-13Fe(s)+2O2(g)=Fe3O4(s)(2)ΔrHmθ(298.15K)=-1117.13kJ·mol-1则反应Fe3O4(s)+4C(石墨)=3Fe(s)+4CO(g)的ΔrHmθ(298.15K)是()kJ·mol-1。


若已知2C(石墨)+O2(g)=2CO(g)(1)ΔrHmθ(298.15K)=-221.04kJ·mol-13Fe(s)+2O2(g)=Fe3O4(s)(2)ΔrHmθ(298.15K)=-1117.13kJ·mol-1则反应Fe3O4(s)+4C(石墨)=3Fe(s)+4CO(g)的ΔrHmθ(298.15K)是()kJ·mol-1。

A.1006.61

B.-1006.61

C.675.05

D.-675.05

正确答案:675.05


Tag:物理化学 石墨 时间:2022-01-03 21:16:40